Attribute Macro pin_project::pin_project [−]
#[pin_project]
An attribute that creates projection types covering all the fields of struct or enum.
This attribute creates projection types according to the following rules:
- For the fields that use
#[pin]attribute, create the pinned reference to the field. - For the other fields, create a normal reference to the field.
And the following methods are implemented on the original type:
fn project(self: Pin<&mut Self>) -> Projection<'_>; fn project_ref(self: Pin<&Self>) -> ProjectionRef<'_>;
By passing an argument with the same name as the method to the attribute, you can name the projection type returned from the method. This allows you to use pattern matching on the projected types.
#[pin_project(project = EnumProj)] enum Enum<T> { Variant(#[pin] T), } impl<T> Enum<T> { fn method(self: Pin<&mut Self>) { let this: EnumProj<'_, T> = self.project(); match this { EnumProj::Variant(x) => { let _: Pin<&mut T> = x; } } } }
Note that the projection types returned by project and project_ref have
an additional lifetime at the beginning of generics.
let this: EnumProj<'_, T> = self.project();
^^
The visibility of the projected types and projection methods is based on the
original type. However, if the visibility of the original type is pub, the
visibility of the projected types and the projection methods is downgraded
to pub(crate).
Safety
This attribute is completely safe. In the absence of other unsafe code
that you write, it is impossible to cause undefined
behavior with this attribute.
This is accomplished by enforcing the four requirements for pin projection stated in the Rust documentation:
-
The struct must only be
Unpinif all the structural fields areUnpin.To enforce this, this attribute will automatically generate an
Unpinimplementation for you, which will require that all structurally pinned fields beUnpin.If you attempt to provide an
Unpinimpl, the blanket impl will then apply to your type, causing a compile-time error due to the conflict with the second impl.If you wish to provide a manual
Unpinimpl, you can do so via theUnsafeUnpinargument. -
The destructor of the struct must not move structural fields out of its argument.
To enforce this, this attribute will generate code like this:
struct MyStruct {} trait MyStructMustNotImplDrop {} impl<T: Drop> MyStructMustNotImplDrop for T {} impl MyStructMustNotImplDrop for MyStruct {}
If you attempt to provide an
Dropimpl, the blanket impl will then apply to your type, causing a compile-time error due to the conflict with the second impl.If you wish to provide a custom
Dropimpl, you can annotate an impl with#[pinned_drop]. This impl takes a pinned version of your struct - that is,Pin<&mut MyStruct>whereMyStructis the type of your struct.You can call
.project()on this type as usual, along with any other methods you have defined. Because your code is never provided with a&mut MyStruct, it is impossible to move out of pin-projectable fields in safe code in your destructor. -
You must make sure that you uphold the
Dropguarantee: once your struct is pinned, the memory that contains the content is not overwritten or deallocated without calling the content’s destructors.Safe code doesn’t need to worry about this - the only way to violate this requirement is to manually deallocate memory (which is
unsafe), or to overwrite a field with something else. Because your custom destructor takesPin<&mut MyStruct>, it’s impossible to obtain a mutable reference to a pin-projected field in safe code. -
You must not offer any other operations that could lead to data being moved out of the structural fields when your type is pinned.
As with requirement 3, it is impossible for safe code to violate this. This crate ensures that safe code can never obtain a mutable reference to
#[pin]fields, which prevents you from ever moving out of them in safe code.
Pin projections are also incompatible with #[repr(packed)]
types. Attempting to use this attribute on a #[repr(packed)] type results
in a compile-time error.
Examples
#[pin_project] can be used on structs and enums.
use std::pin::Pin; use pin_project::pin_project; #[pin_project] struct Struct<T, U> { #[pin] pinned: T, unpinned: U, } impl<T, U> Struct<T, U> { fn method(self: Pin<&mut Self>) { let this = self.project(); let _: Pin<&mut T> = this.pinned; let _: &mut U = this.unpinned; } }
use std::pin::Pin; use pin_project::pin_project; #[pin_project] struct TupleStruct<T, U>(#[pin] T, U); impl<T, U> TupleStruct<T, U> { fn method(self: Pin<&mut Self>) { let this = self.project(); let _: Pin<&mut T> = this.0; let _: &mut U = this.1; } }
To use #[pin_project] on enums, you need to name the projection type
returned from the method.
use std::pin::Pin; use pin_project::pin_project; #[pin_project(project = EnumProj)] enum Enum<T, U> { Tuple(#[pin] T), Struct { field: U }, Unit, } impl<T, U> Enum<T, U> { fn method(self: Pin<&mut Self>) { match self.project() { EnumProj::Tuple(x) => { let _: Pin<&mut T> = x; } EnumProj::Struct { field } => { let _: &mut U = field; } EnumProj::Unit => {} } } }
When #[pin_project] is used on enums, only named projection types and
methods are generated because there is no way to access variants of
projected types without naming it.
For example, in the above example, only the project method is generated,
and the project_ref method is not generated.
(When #[pin_project] is used on structs, both methods are always generated.)
impl<T, U> Enum<T, U> { fn call_project_ref(self: Pin<&Self>) { let _this = self.project_ref(); //~^ ERROR no method named `project_ref` found for struct `Pin<&Enum<T, U>>` in the current scope } }
If you want to call .project() multiple times or later use the
original Pin type, it needs to use .as_mut() to avoid
consuming the Pin.
use std::pin::Pin; use pin_project::pin_project; #[pin_project] struct Struct<T> { #[pin] field: T, } impl<T> Struct<T> { fn call_project_twice(mut self: Pin<&mut Self>) { // `project` consumes `self`, so reborrow the `Pin<&mut Self>` via `as_mut`. self.as_mut().project(); self.as_mut().project(); } }
!Unpin
If you want to ensure that Unpin is not implemented, use the !Unpin
argument to #[pin_project].
use pin_project::pin_project; #[pin_project(!Unpin)] struct Struct<T> { field: T, }
This is equivalent to using #[pin] attribute for the PhantomPinned
field.
use std::marker::PhantomPinned; use pin_project::pin_project; #[pin_project] struct Struct<T> { field: T, #[pin] // <------ This `#[pin]` is required to make `Struct` to `!Unpin`. _pin: PhantomPinned, }
Note that using PhantomPinned without #[pin] attribute has no effect.
UnsafeUnpin
If you want to implement Unpin manually, you must use the UnsafeUnpin
argument to #[pin_project].
use pin_project::{pin_project, UnsafeUnpin}; #[pin_project(UnsafeUnpin)] struct Struct<T, U> { #[pin] pinned: T, unpinned: U, } unsafe impl<T: Unpin, U> UnsafeUnpin for Struct<T, U> {}
Note the usage of the unsafe UnsafeUnpin trait, instead of the usual
Unpin trait. UnsafeUnpin behaves exactly like Unpin, except that
is unsafe to implement. This unsafety comes from the fact that pin
projections are being used. If you implement UnsafeUnpin, you must
ensure that it is only implemented when all pin-projected fields implement
Unpin.
See UnsafeUnpin trait for more details.
#[pinned_drop]
In order to correctly implement pin projections, a type’s Drop impl must
not move out of any structurally pinned fields. Unfortunately,
Drop::drop takes &mut Self, not Pin<&mut Self>.
To ensure that this requirement is upheld, the #[pin_project] attribute
will provide a Drop impl for you. This Drop impl will delegate to
an impl block annotated with #[pinned_drop] if you use the PinnedDrop
argument to #[pin_project].
This impl block acts just like a normal Drop impl,
except for the following two:
dropmethod takesPin<&mut Self>- Name of the trait is
PinnedDrop.
pub trait PinnedDrop { fn drop(self: Pin<&mut Self>); }
#[pin_project] implements the actual Drop trait via PinnedDrop you
implemented. To drop a type that implements PinnedDrop, use the drop
function just like dropping a type that directly implements Drop.
In particular, it will never be called more than once, just like
Drop::drop.
For example:
use std::{fmt::Debug, pin::Pin}; use pin_project::{pin_project, pinned_drop}; #[pin_project(PinnedDrop)] struct PrintOnDrop<T: Debug, U: Debug> { #[pin] pinned_field: T, unpin_field: U, } #[pinned_drop] impl<T: Debug, U: Debug> PinnedDrop for PrintOnDrop<T, U> { fn drop(self: Pin<&mut Self>) { println!("Dropping pinned field: {:?}", self.pinned_field); println!("Dropping unpin field: {:?}", self.unpin_field); } } fn main() { let _x = PrintOnDrop { pinned_field: true, unpin_field: 40 }; }
See also #[pinned_drop] attribute.
project_replace method
In addition to the project and project_ref methods which are always
provided when you use the #[pin_project] attribute, there is a third
method, project_replace which can be useful in some situations. It is
equivalent to Pin::set, except that the unpinned fields are moved and
returned, instead of being dropped in-place.
fn project_replace(self: Pin<&mut Self>, other: Self) -> ProjectionOwned;
The ProjectionOwned type is identical to the Self type, except that
all pinned fields have been replaced by equivalent PhantomData types.
This method is opt-in, because it is only supported for Sized types, and
because it is incompatible with the #[pinned_drop]
attribute described above. It can be enabled by using
#[pin_project(project_replace)].
For example:
use std::{marker::PhantomData, pin::Pin}; use pin_project::pin_project; #[pin_project(project_replace)] struct Struct<T, U> { #[pin] pinned_field: T, unpinned_field: U, } impl<T, U> Struct<T, U> { fn method(self: Pin<&mut Self>, other: Self) { let this = self.project_replace(other); let _: U = this.unpinned_field; let _: PhantomData<T> = this.pinned_field; } }
By passing the value to the project_replace argument, you can name the
returned type of the project_replace method. This is necessary whenever
destructuring the return type of the project_replace method, and work in exactly
the same way as the project and project_ref arguments.
use pin_project::pin_project; #[pin_project(project_replace = EnumProjOwn)] enum Enum<T, U> { A { #[pin] pinned_field: T, unpinned_field: U, }, B, } let mut x = Box::pin(Enum::A { pinned_field: 42, unpinned_field: "hello" }); match x.as_mut().project_replace(Enum::B) { EnumProjOwn::A { unpinned_field, .. } => assert_eq!(unpinned_field, "hello"), EnumProjOwn::B => unreachable!(), }